(5x^-2)/(4x^2)^-2

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Solution for (5x^-2)/(4x^2)^-2 equation: 


D( x )

x = 0

(4*x^2)^-2 = 0

4*x^2 = 0

x = 0

x = 0

(4*x^2)^-2 = 0

(4*x^2)^-2 = 0

1/16*x^-4 = 0 // : 1/16

x^-4 = 0

x należy do O

4*x^2 = 0

4*x^2 = 0

4*x^2 = 0 // : 4

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

(5*x^-2)/((4*x^2)^-2) = 0

80*x^2 = 0 // : 80

x^2 = 0

x = 0

x in { 0} 

x belongs to the empty set

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